1999 Franklin Templeton Tennis Classic – Doubles

From Wikipedia, the free encyclopedia

Doubles
1999 Tennis Channel Open
Final
ChampionsUnited States Justin Gimelstob
United States Richey Reneberg[1]
Runners-upThe Bahamas Mark Knowles
Australia Sandon Stolle
Score6–4, 6–7(4–7), 6–3
Events
Singles Doubles
← 1998 · Tennis Channel Open · 2000 →

Cyril Suk and Michael Tebbutt were the defending champions, but lost in the quarterfinals this year.

Justin Gimelstob and Richey Reneberg won the title, defeating Mark Knowles and Sandon Stolle 6–4, 6–7(4–7), 6–3 in the final.

Seeds[edit]

Draw[edit]

Key[edit]

Finals[edit]

First round Quarterfinals Semifinals Final[1]
1 South Africa E Ferreira
United States R Leach
6 6 6
  United States J Gimelstob
United States R Reneberg
1 7 7   United States J Gimelstob
United States R Reneberg
7 6  
  Czech Republic C Suk
United States M Tebbutt
2 6 6   Czech Republic C Suk
United States M Tebbutt
6 2  
  Argentina P Albano
Argentina D Orsanic
6 4 2   United States J Gimelstob
United States R Reneberg
6 6  
3 Australia J Eagle
Australia P Rafter
3 7 2 Q United States J Palmer
Serbia and Montenegro N Zimonjić
3 3  
LL South Africa C Haggard
North Macedonia A Kitinov
6 5 6 LL South Africa C Haggard
North Macedonia A Kitinov
6 2  
Q United States J Palmer
Serbia and Montenegro N Zimonjić
6 6   Q United States J Palmer
Serbia and Montenegro N Zimonjić
7 6  
WC Australia P Kilderry
Belgium X Malisse
3 1     United States J Gimelstob
United States R Reneberg
6 64 6
  Spain F Roig
Spain J Sánchez
7 4 4 2 The Bahamas M Knowles
Australia S Stolle
4 77 3
WC United States B Bryan
United States M Bryan
6 6 6 WC United States B Bryan
United States M Bryan
1 6 6
  Czech Republic J Novák
Czech Republic D Rikl
7 3 7   Czech Republic J Novák
Czech Republic D Rikl
6 4 4
4 South Africa D Adams
South Africa J-L de Jager
6 6 5 WC United States B Bryan
United States M Bryan
2 6  
WC Canada J Robichaud
United States C Woodruff
7 4 6 2 The Bahamas M Knowles
Australia S Stolle
6 7  
  Australia A Florent
Australia D Macpherson
6 6 7   Australia A Florent
Australia D Macpherson
5 6 4
  United States D Johnson
Australia P Tramacchi
6 7 6 2 The Bahamas M Knowles
Australia S Stolle
7 4 6
2 The Bahamas M Knowles
Australia S Stolle
7 6 7

References[edit]

  1. ^ a b "1999 Scottsdale". International Tennis Federation. Retrieved January 15, 2015.

External links[edit]